Question
3sinx + 4cosx + r is always greater than or equal to 0. What is the smallest value ‘r’ can to take
CAT 2021
Solution
Correct option is
(A)
Explanatory Answer :
3sinx + 4cosx ≥ -r
5(3/5sinx + 4/5cosx) ≥ -r
3/5 = cosA => sinA =4/5
5(sinx cosA + sinA cosx) ≥ -r
5(sin(x + A)) ≥ -r
5sin (x + A) ≥ -r
-1 ≤ sin (angle) ≤ 1
5sin (x + A) ≥ -5
r(min) = 5
hence A is the correct option